Trying to Access Array Offset on Value of Type Null
The code tries to use array access on a variable that is null instead of an array.
Explanation
This error occurs in PHP 7.4+ when you try to access an array offset on a value that is null. For example, if \$result is null and you try \$result['key'], PHP throws this error. This commonly happens when a function or method returns null instead of an array, when a database query returns no results, or when accessing a property that doesn't exist on an object.
Common Causes
- Database query returned null
- Function returning null instead of array
- Missing null check before array access
- API response not in expected format
- Variable assigned null from another function
Solution
Use the null coalescing operator (??) to provide a default value when the variable might be null. Check if the variable is null before accessing array offsets. Use isset() to safely check for array keys. For database results, always check if the result is null or empty before accessing. Use optional() helper in Laravel (optional(\$result)['key']). Consider using typed returns and null return types in your methods to be explicit about possible null values.
Code Example
// This throws the error when $data is null
$data = null;
echo $data['key']; // Trying to access array offset on null
// Function that may return null
function findUser($id) {
return DB::table('users')->find($id); // null if not found
}
$user = findUser(999);
$email = $user['email']; // Error!
// Fix: check for null first
$user = findUser(999);
if ($user) {
$email = $user['email'];
}
// Or use null coalescing
$email = $user['email'] ?? 'Unknown';
// Laravel's optional helper
$email = optional($user)['email'];Error Information
Language
php
Difficulty
Beginner
Views
16
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